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X^2=44+2X
We move all terms to the left:
X^2-(44+2X)=0
We add all the numbers together, and all the variables
X^2-(2X+44)=0
We get rid of parentheses
X^2-2X-44=0
a = 1; b = -2; c = -44;
Δ = b2-4ac
Δ = -22-4·1·(-44)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6\sqrt{5}}{2*1}=\frac{2-6\sqrt{5}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6\sqrt{5}}{2*1}=\frac{2+6\sqrt{5}}{2} $
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